Introduction: In this experiment we use two LED components, each are
rated at different voltages and currents. We need to find the appropriate
resistors and be able to know what real life capabilities are compared to
theory.
Step 1: First we modeled the system with laboratory equipment.
Step 2: We then calculated the theoretical values for the experiment. The two resistor values are shown above.
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The collection of data after calculation and written onto the lab handout. |
Q1: Determine the closest commercially available values for R1 and R2.
The closest values for R1 that we can obtain is 220ohms and for R2 is 420ohms. It would be better to go over the amount of resistance to not burn out the two LEDS.
Step 3: Then we measured the resistors, voltage, and current to ensure we have the right values before assembling the circuit
Step 4: Building the circuit on the breadboard. Eureka the LEDS work! |
a. A 9V Alkaline battery has 0.2A-hr of current.
I_Supply = 33.6 mA
t = 0.2/I_Supply = 5.95 hr
b. Percent Error
LED1 (Yellow) = 40.32%
LED2 (Green) = 23.65%
Resistors are limited to only certain values in real life; different resistors must be used sometimes.
c. P_out = (14.06 mA)*(6.14 V) + (18.59 mA)*(2.14 V) = 114.8 mW
P_in = (33.6 mA)*(9.26 V) = 246.86 mW
Efficiency = P_out/P_in*100% = 36.3%
d. The efficiency would go up because having less power will be going through the resistors.
For the best efficiency, it would be to set the power supply to 5V
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